`

javascript快速排序

 
阅读更多

Stable quicksort in Javascript

October 28th, 2008

Firefox < v3.0 doesn't have a stable Array.sort() function - that is, it doesn't maintain indexes for elements of equal value. This is undefined in the ECMA spec, and has been fixed in Firefox as of version 3 (and curiously enough has been stable in IE all along). As a result, I set out to find a stable, efficient Array.sort() replacement/supplement.

Mergesort is famous for being stable by design, and fast, though not terribly memory efficient. However, it uses a lot of code, and I couldn't manage to find a stable implementation of it.

After doing a little homework, I decided to modify this quicksort pseudocode to get the results I was after. Some would argue that quicksort's worst case performance is slower than mergesort, but for my purposes (small datasets) this was moot.

Here is the resulting code:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
// STABLE implementation of quick sort to replace unstable Array.sort method in Firefox
quickSort = function(arr) {
 
  // return if array is unsortable
  if (arr.length <= 1){
    return arr;
  }
 
  var less = Array(), greater = Array();
 
  // select and remove a pivot value pivot from array
  // a pivot value closer to median of the dataset may result in better performance
  var pivotIndex = Math.floor(arr.length / 2);
  var pivot = arr.splice(pivotIndex, 1)[0];
 
  // step through all array elements
  for (var x = 0; x < arr.length; x++){
 
    // if (current value is less than pivot),
    // OR if (current value is the same as pivot AND this index is less than the index of the pivot in the original array)
    // then push onto end of less array
    if (
      (arr[x] < pivot)
      ||
      (arr[x] == pivot && x < pivotIndex)  // this maintains the original order of values equal to the pivot
    ){
      less.push(arr[x]);
    }
 
    // if (current value is greater than pivot),
    // OR if (current value is the same as pivot AND this index is greater than or equal to the index of the pivot in the original array)
    // then push onto end of greater array
    else {
      greater.push(arr[x]);
    }
  }
 
  // concatenate less+pivot+greater arrays
  return quickSort(less).concat([pivot], quickSort(greater));
};

Of course, this will only sort an array of values (strings, numbers), so to sort an array of objects by a given property, I modified the above to produce:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
// STABLE implementation of quick sort to replace unstable Array.sort method in Firefox
// if sorting an array of objects, key = name of object property to compare
// otherwise leave key undefined
quickSort = function(arr, key) {
 
  // return if array is unsortable
  if (arr.length <= 1){
    return arr;
  }
 
  var less = Array(), greater = Array();
 
  // select and remove a pivot value pivot from array
  // a pivot value closer to median of the dataset may result in better performance
  var pivotIndex = Math.floor(arr.length / 2);
  var pivot = arr.splice(pivotIndex, 1)[0];
 
  // step through all array elements
  for (var x = 0; x < arr.length; x++){
 
    // if (current value is less than pivot),
    // OR if (current value is the same as pivot AND this index is less than the index of the pivot in the original array)
    // then push onto end of less array
    if (
      (
        !key  // no object property name passed
        &&
        (
          (arr[x] < pivot)
          ||
          (arr[x] == pivot && x < pivotIndex)  // this maintains the original order of values equal to the pivot
        )
      )
      ||
      (
        key  // object property name passed
        &&
        (
          (arr[x][key] < pivot[key])
          ||
          (arr[x][key] == pivot[key] && x < pivotIndex)  // this maintains the original order of values equal to the pivot
        )
      )
    ){
      less.push(arr[x]);
    }
 
    // if (current value is greater than pivot),
    // OR if (current value is the same as pivot AND this index is greater than or equal to the index of the pivot in the original array)
    // then push onto end of greater array
    else {
      greater.push(arr[x]);
    }
  }
 
  // concatenate less+pivot+greater arrays
  return quickSort(less, key).concat([pivot], quickSort(greater, key));
};

Code samples

Now we can define an array of objects such as:

1
2
3
4
5
6
var objects = [
  {id: 1, type: 'fruit', name: 'apple', color: 'yellow'},
  {id: 2, type: 'vegetable', name: 'tomato', color: 'red'},
  {id: 3, type: 'fruit', name: 'apple', color: 'red'},
  {id: 4, type: 'vegetable', name: 'pepper', color: 'red'}
];

Then sort by color with a call to:

7
8
9
10
11
12
13
14
15
objects = quickSort(objects, 'color');
 
// sorted
objects = [
  {id: 2, type: 'vegetable', name: 'tomato', color: 'red'},
  {id: 3, type: 'fruit', name: 'apple', color: 'red'},
  {id: 4, type: 'vegetable', name: 'pepper', color: 'red'},
  {id: 1, type: 'fruit', name: 'apple', color: 'yellow'}
];

Then sort by type:

16
17
18
19
20
21
22
23
24
objects = quickSort(objects, 'type');
 
// sorted
objects = [
  {id: 3, type: 'fruit', name: 'apple', color: 'red'},
  {id: 1, type: 'fruit', name: 'apple', color: 'yellow'},
  {id: 2, type: 'vegetable', name: 'tomato', color: 'red'},
  {id: 4, type: 'vegetable', name: 'pepper', color: 'red'}
];

Then sort by name:

25
26
27
28
29
30
31
32
33
objects = quickSort(objects, 'name');
 
// sorted
objects = [
  {id: 3, type: 'fruit', name: 'apple', color: 'red'},
  {id: 1, type: 'fruit', name: 'apple', color: 'yellow'},
  {id: 4, type: 'vegetable', name: 'pepper', color: 'red'},
  {id: 2, type: 'vegetable', name: 'tomato', color: 'red'}
];
分享到:
评论

相关推荐

Global site tag (gtag.js) - Google Analytics